Diagonals of a parallelogram bisect each other.
Here DF and Eg are the diagonals of a parallelogram bisect at point H. So,
GH=EH and DH=FH.
Given DH=4x-10 and FH=x+8. So, we can set up an equation by equalising it.
4x-10= x+8
4x-10-x=x+8-x Subtracting x from each sides.
3x-10=8
3x-10+10=8+10 Adding 10 to each sides.
3x=18
[tex] \frac{3x}{3} =\frac{18}{3} [/tex] Dividing each sides by 3.
x= 6
So, x=6.
