we are given
[tex] y= x^2 + 6x - 5 [/tex]
Firstly ,we can find equation in vertex form
so, we will complete x square
[tex] y= x^2 + 6x+3^2-3^2 - 5 [/tex]
[tex] y= (x+3)^2-3^2 - 5 [/tex]
[tex] y= (x+3)^2-14 [/tex]
now, we can compare it with vertex form of equation
[tex] y= (x-h)^2+k [/tex]
we can find h and k
[tex] h=-3 , k=-14 [/tex]
so, vertex is
[tex] (h,k)=(-3,-14) [/tex].............Answer
