Given: <A = <D
<A = 4x - 20 and <D = x + 19
so
4x - 20 = x + 19
3x = 39
x = 13
<A = 4(13) -20 = 52 - 20 = 32
Answer
<A = 32°
(3)
we are given
angle(A)=angle(D)
A=4x-20
D=x+19
now, we can set it equal
[tex] 4x-20=x+19 [/tex]
now, we can solve for x
[tex] 4x-x=20+19 [/tex]
[tex] 3x=39 [/tex]
[tex] x=13 [/tex]
now, we can find angle A
[tex] A=4*13-20 [/tex]
[tex] A=32 [/tex]..............Answer
