Option A is correct
value of x will cause the denominator of [tex]\frac{8x-2}{5x+1}[/tex] to be 0
To find value of x that make the denominator 0,
We set denominator =0 and solve for x
5x + 1 =0
Subtract 1 from both sides
5x + 1 - 1 = 0 - 1
5x = -1
Divide by 5 on both sides
[tex]\frac{5x}{5} =\frac{-1}{5}[/tex]
So [tex]x =\frac{-1}{5}[/tex]
Option A is correct
