melindamackay83 melindamackay83

04-01-2019
Mathematics

contestada

At the pet fair Darlene’s dog weighed five times as much as leaders dog. Together the dogs weighed 84 pounds how much did each dog weigh?

Respuesta :

musiclover10045 musiclover10045

04-01-2019

Answer:

Let the weight of the leader dog = X

Then Darlene's dog weighs = 5X ( fives times as much)

Now add both together to equal 84 pounds:

5X + X = 84

Simplify:

6x = 84

Divide both sides by 6:

x = 84 / 6

x = 14

The leader dog weighs 14 pounds.

Darlene's dog weighs 70 pounds.

Answer Link

Otras preguntas

Question 1 (1 point) The Harlem Renaissance is noteworthy because Question 1 options: it was the first time in US history a movement started in California and

What is 30/20 converted to a percent

Which of the following choices is excluded from protection by the Antarctic Treaty System? A. Mineral resources in Antarctica B. The atmosphere over Antarctica

What four programs are included in the Social Security Bill ?

What is hs the answer to this question? Y= 5x+5 Y - x=5

What can you conclude about Ian's role at school? A. He is a bully B. He is a model student C. He is a friend to everyone D. He is a teacher's pet I need

Design a product to show your understanding of the zero product property. Include specific values of the variables.

Ronald can read at a constant rate of p pages per minute. Which equation represents the relationship between the total number of pages, N, that Ronald can read

One leg of a right triangle is 7 inches longer than the smaller leg and the hypotenuse is 8 inches longer than the smaller leg. Find the lengths ofl the side o

these are the right answers