Answer:
[tex]x=-3\\y=5\\\\(-3,5)[/tex]
Step-by-step explanation:
Make both equations equal, as following:
[tex]y=y\\x^{2}+12x+32=6x+23[/tex]
Add like terms:
[tex]x^{2}+12x+32-6x-23=0\\x^{2}+6x+9=0[/tex]
Factor it as following:
[tex](x+3)^{2}=0[/tex]
Then:
[tex]x=-3[/tex] (Double root)
Substitute this into the second equation to obtain y:
[tex]y=6(-3)+23\\y=5[/tex]
Then the solution is:
[tex]x=-3\\y=5\\\\(-3,5)[/tex]
