Answer:
B
Step-by-step explanation:
Factor the numerator, that is
x² + 6x + 8 = (x + 4)(x + 2), now
f(x) = [tex]\frac{(x+4)(x+2)}{x+4}[/tex]
Cancel the factor (x + 4) on the numerator/ denominator, leaving
f(x) = x + 2 ← simplified version
Cancelling the factor x + 4 leaves a discontinuity ( a hole ) at
x + 4 = 0 ⇒ x = - 4 and f(- 4) = x + 2 = - 4 + 2 = - 2
There is a discontinuity at (- 4, - 2 )
To find the zero let f(x) = 0, that is
x + 2 = 0 ⇒ x = - 2
The zero is (- 2, 0 )
