sandriyathomas2062 sandriyathomas2062

03-07-2019
Physics

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Water at 0°C loses 1140 calories worth of heat. How much of the water freezes? [Lf= 79.7 cal/g] a) 16.8 g b) 81.5 g c) 0.002 g d) 14.3 g e) 51.0 g

Respuesta :

Vespertilio Vespertilio

06-07-2019

Answer:

option d)

Explanation:

The amount of heat required to convert the 1 g of ice at 0 degree C to 1 g water at 0 degree C is called latent heta of fusion.

H = m Lf

where,, h is the heat required, m is the mass and Lf is the latent heat of fusion

1140 = m x 79.7

m = 14.3 g

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