Answer:
[tex]\large\boxed{p=-\dfrac{3}{2}q}[/tex]
Step-by-step explanation:
[tex]3(p+q)=p\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3p+3q=p\qquad\text{subtract}\ 3q\ \text{from both sides}\\\\3p+3q-3q=p-3q\\\\3p=p-3q\qquad\text{subtract}\ p\ \text{from both sides}\\\\3p-p=p-p-3q\\\\2p=-3q\qquad\text{divide both sides by 2}\\\\\dfrac{2p}{2}=\dfrac{-3q}{2}\\\\\boxed{p=-\dfrac{3}{2}q}[/tex]
