Inezdananabsusanir
Inezdananabsusanir Inezdananabsusanir
  • 01-07-2016
  • Mathematics
contestada

find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

Respuesta :

olemakpadu
olemakpadu olemakpadu
  • 05-07-2016
GS =     a rⁿ ⁻ ¹

t₁ = 7,  a = 7

t₉ = 45927        ar⁹ ⁻ ¹ = ar⁸ = 45927

a =   7           ........(a)

ar⁸ = 45927...........(b)

Equation (b) ÷ (a)

ar⁸/a = 45927/7

r⁸ = 6561

Take the eight root of both sides

⁸√r⁸  =   ⁸√6561

r = 3

Sixth term = ar⁶ ⁻ ¹ = ar⁵ =    7*3⁵ = 1701

Sixth term = 1701
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