Answer:
[tex]\sqrt{32}[/tex]
Step-by-step explanation:
We can first input our numbers into the distance formula to get:
[tex]\sqrt{(5-1)^2+(-1+5)^2}[/tex]
Next we can solve within each parenthesis:
[tex]\sqrt{(4)^2+(4)^2}[/tex]
Next we can solve the squares. The square of 4 is 16 so we can input that into the equation
[tex]\sqrt{16+16}[/tex]
Now we can add the 2 numbers together:
[tex]\sqrt{32}[/tex]
And that is our final number as [tex]\sqrt{32}[/tex] is not a perfect square.
