Answer:
[tex]a_{n}[/tex] = - 3[tex](6)^{n-1}[/tex]
Step-by-step explanation:
Note the common ratio r between consecutive terms, that is
r = - 18 ÷ - 3 = - 108 ÷ - 18 = 6
This indicates the sequence is geometric with n th term ( explicit formula )
[tex]a_{n}[/tex] = a[tex](r)^{n-1}[/tex]
where a is the first term and r the common ratio
Here a = - 3 and r = 6, thus
[tex]a_{n}[/tex] = - 3[tex](6)^{n-1}[/tex]
