Answer:
[tex]cos(D)=0.51[/tex]
[tex]m\angle D=59.49^o[/tex]
Step-by-step explanation:
we know that
In the right triangle DEF
[tex]cos(D)=\frac{DF}{ED}[/tex] ---> by CAH (adjacent side divided by the hypotenuse)
substitute the given values
[tex]cos(D)=\frac{33}{65}=0.51[/tex]
using a calculator
[tex]m\angle D=cos^{-1}(\frac{33}{65})=59.49^o[/tex]
