lizzywolf1234 lizzywolf1234

01-05-2020
Chemistry

contestada

6. What volume of 6M Ba(OH)2 will be needed to neutralize 400.0 ml of a 2.0 M HCl solution?

Respuesta :

valeherrera333 valeherrera333

14-05-2020

Answer:

133 mL

Explanation:

M= mol solute/ L solution

mol solute= M *L solution

mol solute = (2.0 M * 0.4 L)

mol solute= 0.8 mol HCl= mol H

We need the same amount of OH moles to neutralize the solution

L solution = mol solute/M

L solution= 0.8 mol Ba(OH)2/ 6M

L solution=0.133 L=133 mL

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