Answer:
[tex] \dfrac{1}{16} [/tex]
Step-by-step explanation:
Definition of a negative exponent:
[tex] a^{-n} = \dfrac{1}{a^n} [/tex]
This problem:
[tex] 4^{-2} = \dfrac{1}{4^2} = \dfrac{1}{16} [/tex]
The right answer is 1/16
look at the attached picture
Hope it will help you
Good luck on your assignment
