Answer:
[tex]t_7 =\frac{5}{729} [/tex]
Step-by-step explanation:
We are given that:
First term (a) = 5
common ratio (r) =[tex]\frac{1}{3}[/tex]
The nth term of a geometric sequence is given as:
[tex]t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}[/tex]
