qeela
qeela qeela
  • 02-07-2020
  • Mathematics
contestada

Please help ASAP....

Please help ASAP class=

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 05-07-2020

Answer:

  • common ratio: x^2
  • value of x: ±1/2

Step-by-step explanation:

(a) The ratio of adjacent terms is ...

  x^4/x^2 = x^2

The common ratio is x^2.

__

(b) For a geometric sequence with ratio r and first term "a", the sum to infinity is ...

  S = a/(1 -r)

Here, we have ...

  1/3 = x^2/(1 -x^2) . . . . fill in given values for a, r, S

  1 -x^2 = 3x^2 . . . . . cross multiply

  1/4 = x^2

  x = √(1/4)

  x = ±1/2

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