Answer:-
a ∨ ( b ∨ c ) ⇔ (a ∨ b )∨ c ⇔ (a∧b)∨c ⇔(a∧b)→c
Step-by-step explanation:
Explanation :-
we know that b→ c ⇔ b∨c
Replacing b→ c ⇔ b ∨ c , we get
a → b ∨ c ,
By the same rule b→ c ⇔ b∨c
⇒ a ∨ ( b ∨ c )
Now
a ∨ ( b ∨ c ) ⇔ (a ∨ b )∨ c ⇔ (a∧b)∨c ⇔(a∧b)→c
