Answer:
third option
Step-by-step explanation:
Using the rule of radicals
[tex]\frac{\sqrt{a} }{\sqrt{b} }[/tex] = [tex]\sqrt{\frac{a}{b} }[/tex] and [tex]\sqrt{-1}[/tex] = i
Given
[tex]\frac{\sqrt{-12} }{\sqrt{6} }[/tex] = [tex]\sqrt{\frac{-12}{6} }[/tex] = [tex]\sqrt{-2}[/tex] = [tex]\sqrt{2}[/tex] × [tex]\sqrt{-1}[/tex] = i[tex]\sqrt{2}[/tex]
