Answer:
C
Step-by-step explanation:
We are given the function.
[tex]h(x)=e^{2x}[/tex]
And we want to find its inverse.
Let's switch h(x) and x and change h(x) to h⁻¹(x). Hence solve:
[tex]\displaystyle \begin{aligned} x & = e^{2h^{-1}(x)} \\ \\ \ln x & = \ln e^{2h^{-1}(x)} \\ \\ \ln x & = 2h^{-1}(x) \\ \\ h^{-1}(x) & = \frac{1}{2} \ln x\end{aligned}[/tex]
In conclusion, our answer is C.
Note:
[tex]\ln(x)=\log_ex[/tex]
