bhachumanpreet
bhachumanpreet bhachumanpreet
  • 02-10-2020
  • Chemistry
contestada

Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%
NaCl solution.​

Respuesta :

sebassandin
sebassandin sebassandin
  • 07-10-2020

Answer:

[tex]m_{solute}=26.8g[/tex]

Explanation:

Hello.

In this case, since the definition of by-mass percent is:

[tex]\%m/m=\frac{m_{solute}}{m_{solution}}*100\%[/tex]

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

[tex]m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\\ \\m_{solute}=\frac{11.9\%*225g}{100\%}\\ \\m_{solute}=26.8g[/tex]

Best regards.

Answer Link

Otras preguntas

Which phase of the writing process involves checking the content to see if the essay is sufficiently detailed and adequately supports the thesis statement? draf
Why do you think thomas Paine originally published common sense anonymously
first free settlement of africans in America
what is 10% of 400.00
Which part of a scientific argument must be supported by valid data
"It felt as if the whole globe was dressed in snow." Simile or metaphor?
Which algae are responsible for causing red tides that can kill thousands of fish? Chlorophyta Rhodophyta Phaeophyta Pyrrophyta
Why were Japanese Americans in Hawaii not forced to go to internment camps?
On Tuesday Shanice bought five hats. On Wednesday half of all the hats that she had were destroyed. On Thursday there were only 17 left. How many did she have o
How do you find the Greatest Common Factor?