Answer:
[tex]\frac{4+16a^3+23a^3}{a^2}[/tex]
Step-by-step explanation:
Given
[tex]1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15[/tex]
Required
Simplify
[tex]1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15[/tex]
Collect Like Terms
[tex]1/a^2 + 1/a^2 + 2/a^2-3a-5a-8a+2+6+15[/tex]
[tex]1/a^2 + 1/a^2 + 2/a^2-16a+23[/tex]
Add Fractions:
[tex]\frac{1+1+2}{a^2} + 16a + 23[/tex]
[tex]\frac{4}{a^2} + 16a + 23[/tex]
This can be further expressed as:
[tex]\frac{4+16a^3+23a^3}{a^2}[/tex]
