Answer:
I'm assuming you meant [tex]8\leq \frac{2}{3} (3y-6)[/tex], if so the answer is [tex]\:y\ge \:6\:[/tex]
Step-by-step explanation:
hope this helps :)
y_>-6
8<=2y-4
2y-4>=8
2y-4+4>=8+4
2y>=12
2y/2>=12/2
