Respuesta :
Answer:
48.0 grams
Explanation:
The products of this reaction are nitrogen gas and water. How many grams of sodium hydroxide (NaOH) are needed to completely react with 50.0 grams of sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4) and water? 2NaOH + H2SO4 → Na2SO4 + 2H2O ; 48.0 grams of NaOH are needed.
