Answer:
Gusion = 2years
Lesley= 40years
Step-by-step explanation:
Let Guison age be x
Let Lesley age be y
If the sum of the ages of Gusion and Lesley is 42, then;
x+ y =42 ... 1
Four years ago
Guison age = x - 4
Lesley age = y - 4
If four years ago, Gusion was twice as old as Lesley, then;
x - 4 = 2(y-4)
x - 4 = 2y - 9
x - 2y = -9+4
x - 2y = -5 .... 2
Substract 1 from 2;
y + 2y = 1+5
3y = 6
y = 2
From 1;
x = 42 - y
x = 42-2
x = 40
Hence present age pf Guison is 2 years
Present age of Lesley is 40 years
