Given,
Diameter of circle = 6 in.
As we know that radius is half of diameter.
Radius = 6 × 1/2 = 3 inches
Now,
[tex] \sf Circumference \: of \: circle = 2 \pi \: r[/tex]
[tex] = \: 2 \times \dfrac{22}{7} \times 3[/tex]
[tex] = \dfrac{44}{7} \times 3[/tex]
[tex] = \dfrac{132}{7} [/tex]
[tex] = 18.84\: in.[/tex]
Hence,option ( a ) is correct.
