Answer:
Q ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
Explanation:
Three heat transitions need be considered. Cooling the steam to 100°C, condensing the steam to water and cooling the water from 100°C to 87°C.
Total Heat exchange (Q) = ∑ heat transitions
Q = (m·c·ΔT)steam + (m·ΔH)condensation + (m·c·ΔT)water cooling
= (50g x 0.48j/g·°C x 14°C) + (50g x 2259j/g) + (50g x 4.184j/g·°C)
= 24j + 112,950j + 209.2j
= 113,183.2j ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
