Answer:
The range is 17.32 m
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Initial velocity (u) = √2g
Acceleration due to gravity (g) = 10 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine2θ /g
R = (√2g)²Sine 2θ / g
R = 2g² × Sine (2×30) / g
R = 2g × Sine 60
R = 2 × 10 × 0.8660
R = 17.32 m
Therefore, the range is 17.32 m
