Answer:
V = 50.77 L
Explanation:
Given that,
No. of moles, n = 2
Pressure, P = 0.947 atm
Temperature, T = 20°C = 293 K
We need to find the volume occupies by Nitrogen gas. Using gas law,
[tex]PV=nRT\\\\V=\dfrac{nRT}{P}[/tex]
Where
R is gas constant
Put all the values,
[tex]V=\dfrac{2\times 0.08205\times 293}{0.947}\\\\V=50.77\ L[/tex]
So, the volume occupied by the gas is equal to 50.77 L.
