[tex]\huge{ \mathcal{ \underline{ Answer }\: \: ✓ }}[/tex]
According to the unit circle, the value of sin will be :
[tex] \boxed{\boxed{\longrightarrow \dfrac{ - \sqrt{3} }{2} }}[/tex]
Since, value of sin[tex](\theta)[/tex] is always negative in the fourth quadrant, therefore it can't be [tex]\dfrac{1}{2}[/tex].
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