Answer:
[tex]26 > c > 58[/tex]
Step-by-step explanation:
Given
[tex]a,b =42; 16[/tex] --- 2 sides
Required
The inequality for the third side
To do this, we make use of:
[tex]a + b < c[/tex]
[tex]a + c < b[/tex]
[tex]b + c < a[/tex]
So, we have:
[tex]42 + 16 < c[/tex]
[tex]16 + c < 42[/tex]
[tex]42 + c < 16[/tex]
This gives:
[tex]58 < c[/tex]
[tex]c < 26[/tex]
[tex]c<-26[/tex]
The usable inequalities are:
[tex]c < 26[/tex] and [tex]58 < c[/tex]
Rewrite:
[tex]c < 26[/tex] and [tex]c > 58[/tex]
So, the inequality is:
[tex]26 > c > 58[/tex]
