Answer:
[tex]h(x)= 9x - 18[/tex]
Step-by-step explanation:
Given
[tex]f(x) = \frac{1}{9}x + 2[/tex]
Required
The inverse
[tex]f(x) = \frac{1}{9}x + 2[/tex]
Replace f(x) with y
[tex]y = \frac{1}{9}x + 2[/tex]
Swap x and y
[tex]x = \frac{1}{9}y + 2[/tex]
Subtract 2
[tex]x - 2= \frac{1}{9}y[/tex]
Multiply 9
[tex]9x - 18 = y[/tex]
Rewrite as:
[tex]y = 9x - 18[/tex]
So:
[tex]h(x)= 9x - 18[/tex]
