Answer:
[tex]=2x^2+3xy-2y^2[/tex]
Step-by-step explanation:
When given the following problem;
[tex](2x-y)(x+2y)[/tex]
Distribute, multiply every number in one of the parenthesis by every number in the other;
[tex](2x-y)(x+2y)\\=(2x)(x)+(2x)(2y)+(-y)(x)+(2y)(-y)[/tex]
Simplify,
[tex]=(2x)(x)+(2x)(2y)+(-y)(x)+(2y)(-y)\\=2x^2+4xy-xy-2y^2\\=2x^2+3xy-2y^2[/tex]
Therefore, the final answer is;
[tex]=2x^2+3xy-2y^2[/tex]
