sxkloset sxkloset
  • 01-09-2021
  • Mathematics
contestada


a
y = 19.8x + 1080.2

b
y = 19.8x + 1100

c
y = 16.8x + 1080.2

d
y = 16.8x + 1100

a y 198x 10802 b y 198x 1100 c y 168x 10802 d y 168x 1100 class=

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sqdancefan
sqdancefan sqdancefan
  • 02-09-2021

9514 140 393

Answer:

  f(x) = 19.8x +1080.2

Step-by-step explanation:

The given values form an arithmetic sequence with first term (a1) = 1100 and common difference (d) = (1119.80-1100) = 19.80.

The generic term of an arithmetic sequence is ...

  an = a1 +d(n -1)

  an = 1100 +19.8(n -1) = 1080.2 +19.8n

Expressed as a function of x, this is ...

  f(x) = 19.8x +1080.2

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