Respuesta :

Annyohasayo

Answer:

no Luke is not correct.

Step-by-step explanation:

[tex]4r + 5 + 2r \\ colecting \: like \: terms \: \\ 4r + 2r + 5 \\ 6r + 5[/tex]

Schnee

Answer:

Luke is wrong because 4r + 5 + 2r = 6r+5.

You can only add numbers with the same variable, 4r and 2r have the same variable so they can be added while 5 does not have a variable, this means it cannot be added to 4r and 2r.

Step-by-step explanation:

4r + 5 + 2r

4r + 2r + 5

6r + 5