Answer:
x = 2[tex]\sqrt{10}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is
x² + 9² = 11²
x² + 81 = 121 ( subtract 81 from both sides )
x² = 40 ( take square root of both sides )
x = [tex]\sqrt{40}[/tex] = [tex]\sqrt{4(10)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{10}[/tex] = 2[tex]\sqrt{10}[/tex] ≈ 6.32 ( to 2 dec. places )
