[tex]\huge\fbox{Hi~there!~:)}[/tex]
Let's solve this inequality! :)
Let's start by subtracting 10 from both sides:
[tex]\rm{8x\leq 51-10}[/tex]
[tex]\rm{8x\leq 41[/tex]
Now, divide both sides by 8:
[tex]x\leq \displaystyle\frac{41}{8}[/tex] (Answer)
Decimal form:
[tex]\rm{5.125}[/tex]
I hope you find it helpful.
Feel free to ask if you have any doubts.
[tex]\bf{-MistySparkles^**^*[/tex] here to help
