Answer:
[tex]\boxed{\tt y=-\cfrac{4}{3} \:x+2}[/tex]
Step-by-step explanation:
Given the graph, we can see that the line passes through (0,2) and (3,-2).
We are given the y-intercept → (0,2), now, find the slope-intercept form of the line.
[tex]\tt slope=\cfrac{(-2)-2}{3-0}\:\:\boxed{\tt Subtract}[/tex]
[tex]\tt =\cfrac{-4}{3}[/tex]
[tex]\tt =-\cfrac{4}{3}[/tex]
Therefore, the equation that represents the line is:-
[tex]\boxed{\tt y=-\cfrac{4}{3} \:x+2}[/tex]
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