dgsteele06oxmffr
dgsteele06oxmffr dgsteele06oxmffr
  • 04-05-2022
  • Mathematics
contestada

Can someone help me with this?

Can someone help me with this class=

Respuesta :

Hrishii
Hrishii Hrishii
  • 04-05-2022

Answer:

[tex]\huge\purple{ x^2 +(y+2)^2 = 4}[/tex]

Step-by-step explanation:

Circle is centred at (0, -2)

-> h = 0 & k = - 2

radius of the circle (r) = y-coordinate of the center = - 2

Equation of circle in standard form is given as:

[tex](x-h)^2 +(y-k)^2 = r^2[/tex]

Plugging the values of h, k and r in the above equation, we find:

[tex](x-0)^2 +[y-(-2)]^2 = (-2)^2[/tex]

[tex]\implies\huge\orange{ x^2 +(y+2)^2 = 4}[/tex]

This is the required equation of circle.

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