chelsearesquivel
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  • 01-02-2017
  • Mathematics
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6xy (1/2x ^2 - 1/2xy + 1/2y ^2 )

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jdoe0001 jdoe0001
  • 01-02-2017
is this correct on what you typed above -> [tex]\bf 6xy\left( \cfrac{1}{2x^2}-\cfrac{1}{2xy}+\cfrac{1}{2y^2} \right) ?[/tex]
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