janellesmith12 janellesmith12
  • 03-06-2022
  • Mathematics
contestada

Find the 9th term of the geometric sequence 8,32,128,

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loneguy
loneguy loneguy
  • 03-06-2022

[tex]\text{First term,}~ a = 8\\\\\text{Common ratio,}~ r= \dfrac{32}8 = 4\\\\\text{nth term} = ar^{n-1} \\\\\text{9th term} = 8\cdot 4^{9-1}\\\\\\~~~~~~~~~~~~~=8 \cdot 4^8\\\\\\~~~~~~~~~~~~~=524288\\\\\text{The 9th of the geometric sequence is 525288.}[/tex]

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