We have a right triangle.
We can write the Pythagorean theorem as:
[tex]x^2+3.9^2=11^2[/tex]
We add the square of the legs and that is equal to the square of the hypotenuse.
Then, we can rearrange to solve for x as:
[tex]\begin{gathered} x^2+3.9^2=11^2 \\ x^2=11^2-3.9^2 \\ x^2=121-15.21 \\ x^2=105.79 \\ x=\sqrt[]{105.79} \\ x\approx10.3 \end{gathered}[/tex]
Answer:
We can write the Pythagorean theorem as x^2+3.9^2=11^2.
The value of x is approximately 10.3.
