The slope of a straight line is calculated by the formula
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{The two points are:} \\ (x_1,y_1)=(5,\text{ -1)} \\ (x_2,y_2)=(-3,\text{ 3)} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \text{slope}=\frac{3-(-1)}{-3-5} \\ =\frac{3+1}{-8} \\ =\frac{4}{-8} \\ =-\frac{1}{2} \end{gathered}[/tex]Option B is the correct
