[tex]\text{volume of a cone=}\frac{1}{3}\text{ }\pi r^2h[/tex]
Therefore,
[tex]\begin{gathered} r=\frac{2}{2}=1\text{ ft} \\ h=5\text{ ft} \end{gathered}[/tex][tex]\begin{gathered} \text{volume}=\frac{1}{3}\times3.14\times1^2\times5 \\ \text{volume}=\frac{15.7}{3} \\ \text{volume}=5.23333333333 \\ \text{volume}=5.2ft^3 \end{gathered}[/tex]
