For this question we are given:
T2 = 11.4 degrees celsius
V1 = 14.8 cm3
V2=19.9 cm3
We want to know T1. So we need to use Charles Law:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Now if we re-arrange:
[tex]T_1=\frac{T_2V_1}{V_2}[/tex]
So T1 = (11.4 x14.8)/19.9
T1 = 8.48 degrees celsius
