Answer:
Explanation:
When adding polar forms, it is best to convert them to rectangular forms.
[tex]a\angle b=a\cos \theta+j\sin \theta[/tex]Therefore:
[tex]\begin{gathered} 9\angle30=9\cos 30+j\sin 30=4.5\sqrt[]{3}+0.5j \\ 12\angle0=12\cos 0+j\sin 0=1+0j \end{gathered}[/tex]Adding the two results gives:
[tex]\begin{gathered} 9\angle30+12\angle0=(4.5\sqrt[]{3}+0.5j)+1 \\ =(4.5\sqrt[]{3}+1)+0.5j \\ =8.794+0.5j \end{gathered}[/tex]Finally, convert the result to polar form:
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