Given the following trinomial expression:
[tex]x^2+14x+40[/tex]
To factor the trinomial, we need two numbers:
The product of them = 40
The sum of them = 14
The factors of 40 will be as follows:
40 = 1 x 40 ⇒ sum = 41
40 = 2 x 20 ⇒ sum = 22
40 = 4 x 10 ⇒ sum = 14
40 = 5 x 8 ⇒ sum = 13
so, the numbers will be 4 and 10
The factoring of the expression will be as follows:
[tex]x^2+14x+40=(x+4)(x+10)[/tex]
So, the answer will be B. x+10
