SOLUTION
Let one of the numbers be x
Using the statement: The second number is 3 less than twice the first
Then the second number is
[tex]2x-3[/tex]Since, the sum of 2 numbers is 75
It follows:
[tex]x+2x-3=75[/tex]Solve for x
[tex]\begin{gathered} 3x=75+3 \\ 3x=78 \\ x=\frac{78}{3} \\ x=26 \end{gathered}[/tex]Therefore the first number is 24
The second number is
[tex]\begin{gathered} 2(26)-3 \\ =49 \end{gathered}[/tex]therefore the numbers are 49 and 26.
