SOLUTION:
Case: Triangles
Method:
First, It is an Isosceles triangle
When the base angles are equal, the opposite sides are equal too
[tex]x=2\sqrt{6}[/tex]
Next, find y using Pythgoras theorem
[tex]\begin{gathered} y^2=(2\sqrt{6})^2+(2\sqrt{6})^2 \\ y^2=4\times6+4\times6 \\ y^2=24+24 \\ y^2=48 \\ y=\sqrt{48} \\ y=\sqrt{16\times3} \\ y=4\sqrt{3} \end{gathered}[/tex]
Final answer:
[tex]\begin{gathered} x=2\sqrt{6} \\ y=4\sqrt{3} \end{gathered}[/tex]
