To find the y-intercept, we have to make x=0 and solve for y:
[tex]\begin{gathered} 3x-2y=12 \\ x=0 \\ \Rightarrow3\cdot0-2y=12 \\ \Rightarrow-2y=12 \\ \Rightarrow y=\frac{12}{-2}=-6 \\ y=-6 \end{gathered}[/tex]Now, to find the x-intercept, we make y=0 and do the same as the previous case:
[tex]\begin{gathered} y=0 \\ \Rightarrow3x-2\cdot0=12 \\ \Rightarrow3x=12 \\ \Rightarrow x=\frac{12}{3}=4 \\ x=4 \end{gathered}[/tex]therefore, the y-intercept is the point (0,-6) and the x-intercept is the point (4,0)
